Optimal. Leaf size=208 \[ \frac{a (b B-a C) \tan ^2(c+d x)}{b d \left (a^2+b^2\right ) (a+b \tan (c+d x))}-\frac{\left (-2 a^2 C+a b B-b^2 C\right ) \tan (c+d x)}{b^2 d \left (a^2+b^2\right )}+\frac{a^2 \left (a^2 b B-2 a^3 C-4 a b^2 C+3 b^3 B\right ) \log (a+b \tan (c+d x))}{b^3 d \left (a^2+b^2\right )^2}+\frac{\left (a^2 B+2 a b C-b^2 B\right ) \log (\cos (c+d x))}{d \left (a^2+b^2\right )^2}-\frac{x \left (a^2 (-C)+2 a b B+b^2 C\right )}{\left (a^2+b^2\right )^2} \]
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Rubi [A] time = 0.532155, antiderivative size = 208, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 7, integrand size = 40, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.175, Rules used = {3632, 3605, 3647, 3626, 3617, 31, 3475} \[ \frac{a (b B-a C) \tan ^2(c+d x)}{b d \left (a^2+b^2\right ) (a+b \tan (c+d x))}-\frac{\left (-2 a^2 C+a b B-b^2 C\right ) \tan (c+d x)}{b^2 d \left (a^2+b^2\right )}+\frac{a^2 \left (a^2 b B-2 a^3 C-4 a b^2 C+3 b^3 B\right ) \log (a+b \tan (c+d x))}{b^3 d \left (a^2+b^2\right )^2}+\frac{\left (a^2 B+2 a b C-b^2 B\right ) \log (\cos (c+d x))}{d \left (a^2+b^2\right )^2}-\frac{x \left (a^2 (-C)+2 a b B+b^2 C\right )}{\left (a^2+b^2\right )^2} \]
Antiderivative was successfully verified.
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Rule 3632
Rule 3605
Rule 3647
Rule 3626
Rule 3617
Rule 31
Rule 3475
Rubi steps
\begin{align*} \int \frac{\tan ^2(c+d x) \left (B \tan (c+d x)+C \tan ^2(c+d x)\right )}{(a+b \tan (c+d x))^2} \, dx &=\int \frac{\tan ^3(c+d x) (B+C \tan (c+d x))}{(a+b \tan (c+d x))^2} \, dx\\ &=\frac{a (b B-a C) \tan ^2(c+d x)}{b \left (a^2+b^2\right ) d (a+b \tan (c+d x))}+\frac{\int \frac{\tan (c+d x) \left (-2 a (b B-a C)+b (b B-a C) \tan (c+d x)-\left (a b B-2 a^2 C-b^2 C\right ) \tan ^2(c+d x)\right )}{a+b \tan (c+d x)} \, dx}{b \left (a^2+b^2\right )}\\ &=-\frac{\left (a b B-2 a^2 C-b^2 C\right ) \tan (c+d x)}{b^2 \left (a^2+b^2\right ) d}+\frac{a (b B-a C) \tan ^2(c+d x)}{b \left (a^2+b^2\right ) d (a+b \tan (c+d x))}+\frac{\int \frac{a \left (a b B-2 a^2 C-b^2 C\right )-b^2 (a B+b C) \tan (c+d x)+\left (a^2+b^2\right ) (b B-2 a C) \tan ^2(c+d x)}{a+b \tan (c+d x)} \, dx}{b^2 \left (a^2+b^2\right )}\\ &=-\frac{\left (2 a b B-a^2 C+b^2 C\right ) x}{\left (a^2+b^2\right )^2}-\frac{\left (a b B-2 a^2 C-b^2 C\right ) \tan (c+d x)}{b^2 \left (a^2+b^2\right ) d}+\frac{a (b B-a C) \tan ^2(c+d x)}{b \left (a^2+b^2\right ) d (a+b \tan (c+d x))}-\frac{\left (a^2 B-b^2 B+2 a b C\right ) \int \tan (c+d x) \, dx}{\left (a^2+b^2\right )^2}+\frac{\left (a^2 \left (a^2 b B+3 b^3 B-2 a^3 C-4 a b^2 C\right )\right ) \int \frac{1+\tan ^2(c+d x)}{a+b \tan (c+d x)} \, dx}{b^2 \left (a^2+b^2\right )^2}\\ &=-\frac{\left (2 a b B-a^2 C+b^2 C\right ) x}{\left (a^2+b^2\right )^2}+\frac{\left (a^2 B-b^2 B+2 a b C\right ) \log (\cos (c+d x))}{\left (a^2+b^2\right )^2 d}-\frac{\left (a b B-2 a^2 C-b^2 C\right ) \tan (c+d x)}{b^2 \left (a^2+b^2\right ) d}+\frac{a (b B-a C) \tan ^2(c+d x)}{b \left (a^2+b^2\right ) d (a+b \tan (c+d x))}+\frac{\left (a^2 \left (a^2 b B+3 b^3 B-2 a^3 C-4 a b^2 C\right )\right ) \operatorname{Subst}\left (\int \frac{1}{a+x} \, dx,x,b \tan (c+d x)\right )}{b^3 \left (a^2+b^2\right )^2 d}\\ &=-\frac{\left (2 a b B-a^2 C+b^2 C\right ) x}{\left (a^2+b^2\right )^2}+\frac{\left (a^2 B-b^2 B+2 a b C\right ) \log (\cos (c+d x))}{\left (a^2+b^2\right )^2 d}+\frac{a^2 \left (a^2 b B+3 b^3 B-2 a^3 C-4 a b^2 C\right ) \log (a+b \tan (c+d x))}{b^3 \left (a^2+b^2\right )^2 d}-\frac{\left (a b B-2 a^2 C-b^2 C\right ) \tan (c+d x)}{b^2 \left (a^2+b^2\right ) d}+\frac{a (b B-a C) \tan ^2(c+d x)}{b \left (a^2+b^2\right ) d (a+b \tan (c+d x))}\\ \end{align*}
Mathematica [C] time = 4.03853, size = 444, normalized size = 2.13 \[ \frac{2 i a^2 \left (-a^2 b B+2 a^3 C+4 a b^2 C-3 b^3 B\right ) \tan ^{-1}(\tan (c+d x)) (a+b \tan (c+d x))+a \left (2 (a+i b)^2 (c+d x) \left (i a^2 b (B+4 i C)-2 i a^3 C+2 a b^2 (B+i C)+b^3 C\right )+2 \left (a^2+b^2\right )^2 (2 a C-b B) \log (\cos (c+d x))+a^2 \left (a^2 b B-2 a^3 C-4 a b^2 C+3 b^3 B\right ) \log \left ((a \cos (c+d x)+b \sin (c+d x))^2\right )\right )+b \tan (c+d x) \left (2 \left (a^2 b^3 (C (c+d x)+i B (3 c+3 d x+i))+a^3 b^2 C (-4 i c-4 i d x+3)+i a^4 b B (c+d x+i)-2 i a^5 C (c+d x+i)+a b^4 (C-2 B (c+d x))-b^5 C (c+d x)\right )+2 \left (a^2+b^2\right )^2 (2 a C-b B) \log (\cos (c+d x))+a^2 \left (a^2 b B-2 a^3 C-4 a b^2 C+3 b^3 B\right ) \log \left ((a \cos (c+d x)+b \sin (c+d x))^2\right )\right )+2 b^2 C \left (a^2+b^2\right )^2 \tan ^2(c+d x)}{2 b^3 d \left (a^2+b^2\right )^2 (a+b \tan (c+d x))} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.043, size = 364, normalized size = 1.8 \begin{align*}{\frac{C\tan \left ( dx+c \right ) }{{b}^{2}d}}-{\frac{\ln \left ( 1+ \left ( \tan \left ( dx+c \right ) \right ) ^{2} \right ){a}^{2}B}{2\,d \left ({a}^{2}+{b}^{2} \right ) ^{2}}}+{\frac{\ln \left ( 1+ \left ( \tan \left ( dx+c \right ) \right ) ^{2} \right ){b}^{2}B}{2\,d \left ({a}^{2}+{b}^{2} \right ) ^{2}}}-{\frac{\ln \left ( 1+ \left ( \tan \left ( dx+c \right ) \right ) ^{2} \right ) Cab}{d \left ({a}^{2}+{b}^{2} \right ) ^{2}}}-2\,{\frac{B\arctan \left ( \tan \left ( dx+c \right ) \right ) ab}{d \left ({a}^{2}+{b}^{2} \right ) ^{2}}}+{\frac{C\arctan \left ( \tan \left ( dx+c \right ) \right ){a}^{2}}{d \left ({a}^{2}+{b}^{2} \right ) ^{2}}}-{\frac{C\arctan \left ( \tan \left ( dx+c \right ) \right ){b}^{2}}{d \left ({a}^{2}+{b}^{2} \right ) ^{2}}}+{\frac{{a}^{4}\ln \left ( a+b\tan \left ( dx+c \right ) \right ) B}{{b}^{2}d \left ({a}^{2}+{b}^{2} \right ) ^{2}}}+3\,{\frac{{a}^{2}\ln \left ( a+b\tan \left ( dx+c \right ) \right ) B}{d \left ({a}^{2}+{b}^{2} \right ) ^{2}}}-2\,{\frac{{a}^{5}\ln \left ( a+b\tan \left ( dx+c \right ) \right ) C}{{b}^{3}d \left ({a}^{2}+{b}^{2} \right ) ^{2}}}-4\,{\frac{{a}^{3}\ln \left ( a+b\tan \left ( dx+c \right ) \right ) C}{bd \left ({a}^{2}+{b}^{2} \right ) ^{2}}}+{\frac{B{a}^{3}}{{b}^{2}d \left ({a}^{2}+{b}^{2} \right ) \left ( a+b\tan \left ( dx+c \right ) \right ) }}-{\frac{C{a}^{4}}{{b}^{3}d \left ({a}^{2}+{b}^{2} \right ) \left ( a+b\tan \left ( dx+c \right ) \right ) }} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.7175, size = 297, normalized size = 1.43 \begin{align*} \frac{\frac{2 \,{\left (C a^{2} - 2 \, B a b - C b^{2}\right )}{\left (d x + c\right )}}{a^{4} + 2 \, a^{2} b^{2} + b^{4}} - \frac{2 \,{\left (2 \, C a^{5} - B a^{4} b + 4 \, C a^{3} b^{2} - 3 \, B a^{2} b^{3}\right )} \log \left (b \tan \left (d x + c\right ) + a\right )}{a^{4} b^{3} + 2 \, a^{2} b^{5} + b^{7}} - \frac{{\left (B a^{2} + 2 \, C a b - B b^{2}\right )} \log \left (\tan \left (d x + c\right )^{2} + 1\right )}{a^{4} + 2 \, a^{2} b^{2} + b^{4}} - \frac{2 \,{\left (C a^{4} - B a^{3} b\right )}}{a^{3} b^{3} + a b^{5} +{\left (a^{2} b^{4} + b^{6}\right )} \tan \left (d x + c\right )} + \frac{2 \, C \tan \left (d x + c\right )}{b^{2}}}{2 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.46194, size = 936, normalized size = 4.5 \begin{align*} -\frac{2 \, C a^{4} b^{2} - 2 \, B a^{3} b^{3} - 2 \,{\left (C a^{3} b^{3} - 2 \, B a^{2} b^{4} - C a b^{5}\right )} d x - 2 \,{\left (C a^{4} b^{2} + 2 \, C a^{2} b^{4} + C b^{6}\right )} \tan \left (d x + c\right )^{2} +{\left (2 \, C a^{6} - B a^{5} b + 4 \, C a^{4} b^{2} - 3 \, B a^{3} b^{3} +{\left (2 \, C a^{5} b - B a^{4} b^{2} + 4 \, C a^{3} b^{3} - 3 \, B a^{2} b^{4}\right )} \tan \left (d x + c\right )\right )} \log \left (\frac{b^{2} \tan \left (d x + c\right )^{2} + 2 \, a b \tan \left (d x + c\right ) + a^{2}}{\tan \left (d x + c\right )^{2} + 1}\right ) -{\left (2 \, C a^{6} - B a^{5} b + 4 \, C a^{4} b^{2} - 2 \, B a^{3} b^{3} + 2 \, C a^{2} b^{4} - B a b^{5} +{\left (2 \, C a^{5} b - B a^{4} b^{2} + 4 \, C a^{3} b^{3} - 2 \, B a^{2} b^{4} + 2 \, C a b^{5} - B b^{6}\right )} \tan \left (d x + c\right )\right )} \log \left (\frac{1}{\tan \left (d x + c\right )^{2} + 1}\right ) - 2 \,{\left (2 \, C a^{5} b - B a^{4} b^{2} + 2 \, C a^{3} b^{3} + C a b^{5} +{\left (C a^{2} b^{4} - 2 \, B a b^{5} - C b^{6}\right )} d x\right )} \tan \left (d x + c\right )}{2 \,{\left ({\left (a^{4} b^{4} + 2 \, a^{2} b^{6} + b^{8}\right )} d \tan \left (d x + c\right ) +{\left (a^{5} b^{3} + 2 \, a^{3} b^{5} + a b^{7}\right )} d\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: AttributeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.88942, size = 392, normalized size = 1.88 \begin{align*} \frac{\frac{2 \,{\left (C a^{2} - 2 \, B a b - C b^{2}\right )}{\left (d x + c\right )}}{a^{4} + 2 \, a^{2} b^{2} + b^{4}} - \frac{{\left (B a^{2} + 2 \, C a b - B b^{2}\right )} \log \left (\tan \left (d x + c\right )^{2} + 1\right )}{a^{4} + 2 \, a^{2} b^{2} + b^{4}} - \frac{2 \,{\left (2 \, C a^{5} - B a^{4} b + 4 \, C a^{3} b^{2} - 3 \, B a^{2} b^{3}\right )} \log \left ({\left | b \tan \left (d x + c\right ) + a \right |}\right )}{a^{4} b^{3} + 2 \, a^{2} b^{5} + b^{7}} + \frac{2 \, C \tan \left (d x + c\right )}{b^{2}} + \frac{2 \,{\left (2 \, C a^{5} b \tan \left (d x + c\right ) - B a^{4} b^{2} \tan \left (d x + c\right ) + 4 \, C a^{3} b^{3} \tan \left (d x + c\right ) - 3 \, B a^{2} b^{4} \tan \left (d x + c\right ) + C a^{6} + 3 \, C a^{4} b^{2} - 2 \, B a^{3} b^{3}\right )}}{{\left (a^{4} b^{3} + 2 \, a^{2} b^{5} + b^{7}\right )}{\left (b \tan \left (d x + c\right ) + a\right )}}}{2 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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